As a sequel to my question How to solve $0.5^{1200}\times (2^{1204})$? :
$\frac{2^{900}*7^{898}}{14^{897}}$
Will I first solve the upper raw like did in previous question and then anwser $14^{897}$
As a sequel to my question How to solve $0.5^{1200}\times (2^{1204})$? :
$\frac{2^{900}*7^{898}}{14^{897}}$
Will I first solve the upper raw like did in previous question and then anwser $14^{897}$
$$\frac{2^{900}\cdot 7^{898}}{14^{897}} = \frac{2^{900}\cdot 7^{898}}{(2\cdot 7)^{897}} = \frac{2^{900}\cdot 7^{898}}{2^{897}\cdot 7^{897}}$$ $$= 2^{900 - 897}\cdot 7^{898-897} = 2^3\cdot 7^1 = 8\cdot 7 = 56$$