Rigorously deriving the solution of the differential equations system $\frac{d}{dt}\mathbf{y}(t) = \mathbf{A} y(t)$

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The unique solution of the linear ordinary differential equation system $$\frac{d}{dt}\mathbf{y}(t) = \mathbf{A} \mathbf {y}(t)$$ is supposedly given by $$\mathbf{y}(t) = (\sum_{k=0}^{\infty} \frac{1}{k!}(\mathbf{A}t)^k)\mathbf{y}(0)$$ where $\mathbf{A}$ is a real or complex matrix (cf. linear differential equations system).

How to derive this rigorously (and not just prove it by plugging it in the original differential equation)?

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From the given equation,

$$\frac{d^2}{dt^2}\mathbf y(t)=\frac{d}{dt}\mathbf A\mathbf y(t)=\mathbf A\frac{d}{dt}\mathbf y(t)=\mathbf A^2\mathbf y(t)$$

and by induction $$\frac{d^n}{dt^n}\mathbf y(t)=\mathbf A^n\mathbf y(t).$$

Then by a simple application of Taylor around $t=0$,

$$\mathbf y(t)=\sum_{n=0}^\infty\left.\frac{d^n}{dt^n}\mathbf y(t)\right|_{t=0}\frac{t^n}{n!}=\sum_{n=0}^\infty\mathbf A^n\mathbf y(0)\frac{t^n}{n!}=\sum_{n=0}^\infty\frac{(\mathbf At)^n}{n!}\mathbf y(0).$$


Uniqueness can probably be established using the Picard-Lindelöf theorem.