Root of $x\sin x-1=0$ using fixed point iteration

1.7k Views Asked by At

How to find the root of the equation $x\sin x-1=0$ between [2 , 3] using fixed point iteration? I tried $x=1/\sin x$ and $x=\arcsin (1/x)$ but does not converge the root between [2 , 3].

1

There are 1 best solutions below

6
On BEST ANSWER

The arcsine always returns a value in $[-\pi/2,\pi/2]$ so you want $x=\pi-\arcsin(1/x)$