My attempt
Product of roots=(-1)^n sincep(-1)=0 and given no roots inside the unit disc.Hence no roots outside the unit disc.
Then all the roots are on the unit circle.
Hence p(2)>0 true, p(3)=0 false.
Is p(1)=0
2026-03-28 20:07:10.1774728430
Roots of a Monic polynomial
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Hint: $\;p(0)=-1$ and $\,\lim_{x \to \infty}p(x) = + \infty\,$ on the real axis, so if $p(1) \ne 0$ there would exist at least one real root either inside $(0,1)$ or in $(1, \infty)$. In the latter case, consider that
all the roots are on the unit circlemeans that $x^n\,p(1/x)$ has all roots on the unit circle as well.