Suppose the primes p and q used in the RSA algorithm are consecutive primes (meaning they differ by 2). How would you factor n = pq?
The ciphertext 10787770728 was encrypted using n = 10993522499 and e = 113. The factors p and q of n were chosen so that p - q = 2. Use your method in part (a) to decrypt the message
2026-03-27 07:11:54.1774595514
RSA Algorithm Question
1.2k Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
Set $n^2-1=10993522499$.
Isolate $n^2$.
$n$ is its positive square root.
Your two factors are $n-1$ and $n+1$.