Let $\mathbb{T}^2 = [0,1]^2/\sim$ be the torus, and $S_1,S_2 \subset \mathbb{T}^2$ are smooth $1$-manifolds such that $$S_i =\dot{\bigcup}_{j=1}^{n_i} C_{j}^{i}, $$ where each $C_j^{i}$ is a $1$-manifold diffeomorphic to $\mathbb{S}^1$.
Let $L_{\varepsilon,\delta}: \mathbb{T}^2 \to \mathbb{T}^2 $ be the smooth diffeomorphism $$L_{\varepsilon,\delta}\left([x,y]\right) = [x+\varepsilon,y+\delta].$$
My Question: Is it possible guarantee that there exists $(\varepsilon, \delta)\in \mathbb{R}^2$, such that $L_{\varepsilon,\delta}(S_1) \pitchfork S_2$?
I don't have any good idea on how to solve this problem, can anyone help me?
I tried to find a smart way to apply the transversality theorem but it led me to nowhere.
Just for the records, the definitions that I'm using:
Besides that, there exists the following well-known theorem
The above theorem also holds if we change word "residual" to "full measure set" (complementary of a null set).
The demonstration follows immediately from the fact that the function
$$F: S_1 \times \mathbb{R}^2 \to \mathbb{T}^2 $$ $$([p],\varepsilon,\delta)\mapsto [p + (\varepsilon,\delta)] $$
satisfies $F \pitchfork S_2$, because $\text{d}F_q$ is obviously surjective. Then follows from Theorem 1 that the set $\{(\varepsilon,\delta) \in \mathbb{R}^2;$ $F(\cdot,\varepsilon,\delta) \pitchfork S_2\}$ isn't empty.