Second derivative of implicit function - answer not matching

Question

I have an implicit function $y(x)$ defined with the equation.

$\sin{(x+y)} - y = 0$

I have to find the first and second derivatives of $y$ w.r.t. $x$.

When I am solving it myself I am getting

$$y' = \frac{\cos{(x+y)}} {(1 - \cos{(x+y)})}$$

$$y'' = \frac{-\sin{(x+y)}} {(1 - \cos{(x+y)})^3}$$

But the answer I have (in the book) for $y''$ does not have the minus sign before $\sin(x+y)$.

1. Which one is correct?

2. How do I calculate these $y'$ and $y''$ with Wolfram Alpha, is it possible?

Thanks in advance.