Is there two semidirect products of order $16$ with $C_2$ normal subgroup?
How many groups of the form $C_4 \times C_2$ : $C_2$ are there ?
Is it one expression for two groups ? or more?
Is there two semidirect products of order $16$ with $C_2$ normal subgroup?
How many groups of the form $C_4 \times C_2$ : $C_2$ are there ?
Is it one expression for two groups ? or more?
On
A semi direct product $A\rtimes B$ is given by a group action of $B$ onto $A$, or equivalently by a group homomorphism $B\to \mathrm{Aut}(A)$, where $\mathrm{Aut}(A)$ is the group of automorphisms of $A$. Moreover, the semi direct product is isomorphic to $A\times B$ if the action is trivial.
In your case, the normal subgroup $A$ is of size $2$, so there are two elements, one is the identity and the other of order $2$. You cannot switch them, so $\mathrm{Aut}(A)$ is trivial. Hence, $A\rtimes B=A\times B$ for each group $B$, if $A$ is of size $2$.
If you try to do the converse, so take $A=C_4\times C_2$ and $B=C_2$, then you need to find an action of $B$ onto $A$.
There are two groups with structure description $(C_4\times C_2)\rtimes C_2$ whose Gap Ids are $(16,3)$ and $(16,13)$. You may see this for more detail.