Set of injective operators is a dense residual set in $\mathcal{B}(\mathfrak{X})$

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Let $\mathfrak{X}$ be a Banach space and $\mathcal{B}(\mathfrak{X})$ the set of bounded linear operators mapping $\mathfrak{X}$ to $\mathfrak{X}$. In [1] below it is shown that the set of invertible operators is not necessarily dense in $\mathcal{B}(\mathfrak{X})$, although it is well known that it is an open set. In [2], it is shown that the set of injections (I suppose we may call this $\mathcal{I}(\mathfrak{X})$) is not necessarily open in $\mathcal{B}(\mathfrak{X})$.

My question is on how "common" injectiveness is in $\mathcal{B}(\mathfrak{X})$. In particular, the results above leave open the possibility that $\mathcal{I}(\mathfrak{X})$ is a dense $G_\delta$ set, and so topologically generic. In either case, it would be interesting to know whether density or the $G_\delta$ condition hold. I believe that the spectral theorem already implies that normal operators on Hilbert spaces may be approximated by injective operators (see for instance [3]). Any results that you guys know of would be appreciated!

[1] Showing that $\mathcal{G}(\ell_2)$ is not dense in $\mathcal{B}(\ell_2)$ via the right shift

[2] Do bounded linear operators on a Banach space which are injective or have dense range form an open subspace?

[3] The set of invertible normal operator is dense in the set of normal operator