set-theory (anti-symmetric)

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in relation, anti-symmetric -> if xRy and yRx, then x=y.

Today, my lecturer said that relation $<$, which represents $(\le \bigwedge\ne)$, satisfies anti-symmetric. He did not prove it and He left it for us to exercise. I have no idea why anti-symmetric is satisfied when the relation is $<$.

Can anyone please explain? thanks

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I will assume that by $<$ you mean the "less than" relation on some totally ordered set such as the real numbers.

Is there ever a situation where you have $x<y$ AND $y<x$ at the same time?

No.

The statement then is an example of a Vacuous Truth since the premise is always false, there is no possible way that there is a contradiction.

A statement is only false if the premise is true while the conclusion is false.