Given set $A={1, 2, 3}$ consider the following relation on $A$
$R=\{(1, 1), (2, 1), (3, 3), (3, 2)\}$
Which one of the following statements are true
- $R$ is antisymmetric and transitive
- $R$ is antisymmetric but not transitive
- $R$ is not transitive and not antisymmetric
- $R$ is reflexive and antisymmetric
I have 4 as the answer, because:
- $R$ is reflexive: $(1, 1), (3, 3)$
- $R$ is antisymmetric: $(2, 1), (3, 2)$ are in $R$ but not $(1, 2), (2, 3)$
But there may also be a case for transitivity because of $(2, 1), (3, 2)$
I'm at a bit of a loss really
The relation is not reflexive because $(2,2)\notin R$. Remember that the definition of reflexivity is that $(a,a)\in R$ for all $a\in A$.
Also, the relation is not transitive, because $(3,2)\in R$ and $(2,1)\in R$, but $(3,1)\notin R$.
Finally, a relation is antisymmetric if the conditions $(a,b)\in R$ and $(b,a)\in R$ imply $a=b$. Is this true in the $R$ you've given?