Let $0\to N\stackrel{f}{\to} E\stackrel{g}{\to} M\to 0$ be a short exact sequence of $R$-modules. Let $\varphi:N\to N'$ be a morphism of $R$-modules and let $E'$ be the pushout of $N\to E$ and $\varphi:N\to N'$. Show that there is a short exact sequence $0\to N'\to E'\to M\to 0$ of $R$-modules.
My try:
$0\circ \phi=g\circ f$ so by universal property of pullback $\exists \psi:E'\to M$ such that $\psi\circ \ell=0$.
Now $\psi$ is surjective since $g$ is and $\ell\circ k=g$.
Now it remains to show that $Im \ell=Ker \psi$ and $\ell$ injective. Does anyone have ideas about this?

Hint and answer to one of your questions: You can take zero map $0:N'\to M$. Then $0=0\circ\varphi=g\circ f$, and from universal property of pushout you get map $\psi:E'\to M$ such that $\psi\circ (N'\to E')=0$.