Shorter proof for some equvalences

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Let $(G,\cdot)$ be a group show that

A) $G$ is abelian

B) For all $x,y\in G: (xy)^{-1}=x^{-1}y^{-1}$

C) For all $x,y\in G: (xy)^{2}=x^{2}y^{2}$

D) There existst an $n\in \mathbb{Z}$ such that for all $x,y\in G$

$\displaystyle (xy)^{n-1}=x^{n-1}y^{n-1}$ and $\displaystyle (xy)^{n}=x^{n}y^{n}$ and $\displaystyle (xy)^{n+1}=x^{n+1}y^{n+1}$

are equivalent.


I showed $A\iff B,A\iff C$ and $A\iff D$. That was not really hard, except maybe $D\Rightarrow A$. I would like to do a circular argument, but i have no idea how. Any hints?

Thanks in advance!

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So you're basically asking how to prove that B)$\implies$C) and C)$\implies$D).

$\bbox[5px,border:2px solid #4B0082]{B)\implies C)}$

Note that $$\begin{align} \forall x,y\in G\left((xy)^{-1}=x^{-1}y^{-1}\right) &\implies \forall x,y\in G\left(y^{-1}x^{-1}=x^{-1}y^{-1}\right)\\ &\implies \forall x,y\in G\left(xy=yx\right)\\ &\implies \forall x,y\in G\left((xy)^2=x^2y^2\right).\end{align}$$

$\bbox[5px,border:2px solid #4B0082]{C)\implies D)}$

As noted by Seth in the comments, assume C) is true and let $n=1$.