There is a sytem $Ax=b$ with rank A not necessarily n
How to prove that
$A^TAx=A^Tb$
Has a solution?
2026-03-27 14:21:34.1774621294
show $A^TAx=A^Tb$ has a solution with Rank (A) not necessarily n
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Hint: $x$ is a solution exactly when $Ax-b\in \ker A^T$.