Show $\frac{1}{(2+jw)^2}*\frac{1}{4+jw} $ equal to $\frac{1}{4(4+jw)}-\frac{1}{4(2+jw)}+\frac{1}{2(2+jw)^2}$

Question

Show $\frac{1}{(2+jw)^2}*\frac{1}{4+jw} $ equal to $\frac{1}{4(4+jw)}-\frac{1}{4(2+jw)}+\frac{1}{2(2+jw)^2}$

No idea to do it.Please give hint.

Answer 1

Just check it

$$\frac{1}{4(4+jw)}-\frac{1}{4(2+jw)}+\frac{1}{2(2+jw)^2}=\frac{(2+jw)^2-(4+jw)(2+jw)+2(4+jw)}{4(4+jw)(2+jw)^2}=\ldots$$