Show $\int_{a}^{b}f(x) dx = A$

77 Views Asked by At

I've been assigned the following problem for my Real Analysis class and I'm not sure how to go about it.

"Suppose that $\int_{a}^{b}f(x)dx$ exists and $\exists$ A such that, $\forall \epsilon>0$ and $\delta>0$, there is a partition P of [a,b] with $\left\Vert P \right\Vert < \delta$ and a Riemann sum $\sigma$ of $f$ over P that satisfies the inequality $\left|\sigma -A\right|<\epsilon.$ "

Show that $\int_{a}^{b}f(x) dx = A$

EDIT:

My work:

Since $f$ is defined on $[a,b]$ and $\exists A$ such that $\forall \epsilon>0, \exists \delta >0$, then $\left|\sigma -A\right|<\epsilon$.

Also, since $\sigma$ is any Riemann sum of $f$ over partition P of [a,b] such that $\left\Vert P \right\Vert < \delta$

I can say that $A$ is the Riemann Integral of $f$ over [a,b],

or that, $$\int_{a}^{b}f(x) dx = A$$