Show $T|_{M}$ is a compact operator

69 Views Asked by At

Let $T$ be a compact operator and suppose $M$ is an invariant subspace for $T$. I need to show that $T|_M$ is compact.

Any hint on how to begin with this problem?

1

There are 1 best solutions below

0
On BEST ANSWER

$T$ (defined on $X$) is compact is equivalent to saying that the image of the unit ball is contained in a compact set. The unit ball of $M$ is a closed subset of the unit ball of $X$, so the adherence of its image is contained in the adherence of the image of the unit ball of $X$ so it is compact.