Show that 4*AB=CAB is not possible

Question

Show that 4*AB=CAB is not possible.Each letter denotes a single digit.It could be noted that since LHS is a multiple of 4,thus RHS would also be a multiple of 4.That's all i conclude yet...

Answer 1

Hint: what digit $d$ has the property that $4 \times d$ ends in $d$?

Answer 2

Well, a start could be to treat AB as a variable, $AB = \alpha$ and solve

$4*\alpha = C*100 + \alpha$

If this equation has no solutions where $\alpha$ is a whole number with two digits, then the original statement is not possible since $\alpha$ is AB, which is a whole number with two digits.

Oh, and C has to be between 0 and 9 too right?