Show that $(\aleph)^{\aleph_0} < (\aleph_0)^{\aleph} $

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Couldn't find answers like that, so I would ask.

At first, let's note that ${\aleph}=c $ in our case. Now, we need to show that: $$(\aleph)^{\aleph_0} < (\aleph_0)^{\aleph} $$

For the left part of this inequality, we know that $\aleph^{\aleph_0}=2^{\aleph_0\aleph_0}=\aleph$.

But for the right part, can we assume that ${\aleph_0}^{\aleph}={\aleph_0}^{\aleph_0}⋅{\aleph_0}^{\aleph}={\aleph}⋅{\aleph_0}^{\aleph}$,

thus making it greater than $\aleph^{\aleph_0}$?

Thanks!