Show that $e^{z+z^3/3}$ is Hayman admissable

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Show that $f(z) := e^{z+\frac{z^3}{3}}$ is Hayman admissable.

Remark: You can find the relevant definition from p.565 of the Floyd & Sedgewick book below.

From the lecture I know the following theorem:

Let $P(z)$ be a polynomial with real coefficients. If the Taylor coefficients of $e^{P(z)}$ are positive for large ennough $n$, then $e^{P(z)}$ is Hayman admissable.

I would say that this already solves the exercise, since

$$\exp(z) := \sum_{n \ge 0} \frac{z^n}{n!}$$

is always positive and thus also $e^{z+\frac{z^3}{3}}$. Is it really that easy or am I missing something here?enter image description here