Show that $f^t \circ f^t=0.$

Question

Let $V$ be vector space over a field $K$ and let $f$ be a linear operator on $V$. Suppose that $f \circ f=0.$

Show that $f^t \circ f^t=0.$

Is this really as simple as noting that $f^t \circ f^t=(f\circ f)^t=0$ or is there more to it than that?