I have no clue about how to go about this question. I feel like I need more info, but I don't know, please help.
2026-04-04 20:44:20.1775335460
Show that if $b\mid c$ and $b > \gcd(c, d)$, then $b\nmid d$.
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hint: Use proof by contradiction:
Assume $b\mid c$ and $b\gt \gcd(c, d).$
Now suppose, for the sake of contradiction, that $b\mid d$.
So, if $b$ divides $c$ and $b$ divides $d$, then $b \mid \gcd(c, d).\quad$ (Why?).
But ...