Let $P(z) = 2z^4-5z^3+4z^2-5z+2.$
if $w$ is a zero of $P(z)$ show that $1/w$ is also a zero of that polynomial.
Just note that $z^4P(\dfrac1z)=P(z)$.
We must substitute $$w->\frac{1}{w}$$ in your equation: $$\frac{2}{w^4}-\frac{5}{w^3}+\frac{4}{w^2}-\frac{5}{w}+2$$ and this must be zero if $$2w^4-5w^3+4w^2-5w+2=0$$
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Just note that $z^4P(\dfrac1z)=P(z)$.