Show that $\int d^2\vec{r} \frac{e^{i \vec{q} \vec{r}}}{(1+r^2)^{3/2}}=2 \pi e^{-q}$

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I am trying to compute the 2-d Fourier transform: $$I=\int d^2\vec{r} \frac{e^{i \vec{q} \vec{r}}}{(1+r^2)^{3/2}}$$ In polar coordinates the integral looks like:

$$I=\int^{2\pi}_0d \theta \int^{\infty}_0 dr \frac{r}{(1+r^2)^{3/2}}e^{i q r \cos\theta}$$

I have tried to integrate over the angle first to get a Bessel function, but when I expand it as a series, the integral over $r$ do not converge.

Mathematica gives a simple answer, that is why I am curious on how to derive it.