Show that : $\mathcal{X} +\mathcal {Y} =\{X+Y : X\in \mathcal{X} , Y\in\mathcal {Y} \}$ is uniformly integrable

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Let $(\Omega,\mathcal{F},\mathbb{P})$ be a probability space and $\mathcal{X} $, $\mathcal {Y} $ be two uniformly-integrable families on the same probability space $\Omega $.

Show that the following familie is also uniformly integrable: $$ \mathcal{X} +\mathcal {Y} =\{X+Y : X\in \mathcal{X} , Y\in\mathcal {Y} \}. $$

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A family $\{X_i\}$ is uniformly integrable iff

a) $\sup_i E|X_i| <\infty$ and

b) for every $\epsilon >0$ there exists $\delta >0$ such that $\int_E |X_i|dP <\epsilon$ whenever $P(E) <\delta$.

Now you only need $|a+b| \leq |a|+|b|$ to verify that these two properties are satisfied by the sum $\mathcal X +\mathcal Y $