Show that $P(\mathbb{N})$ is equivalent to $2^\mathbb{N}$

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How would I show that $P(\mathbb{N})$ is equivalent to $2^\mathbb{N}$? The questions asks to form a theorem from the statement I just gave. Any help would be appreciated.

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Show that the map sending $A\subset\mathbb{N}$ to its indicator function $I(A)$ is a bijection.