Show that $\text{ker}(T^*T)=\text{ker}(T)$
In my solutions when showing that $x\in\text{ker}(T)\implies x\in\text{ker}(T^*T)$ the following is given:
$$x\in\text{ker}(T)\implies Tx=0\implies T^*Tx=0\implies x\in\text{ker}(T^*T)$$
How exactly does $Tx=0\implies T^*Tx=0$ ?
$T^*$ is a linear operator, hence $T^*(0)=0$.