Show that $\textrm{trace}: \textrm{End}(V)\rightarrow k$ defined by $\textrm{trace}(\phi ):=\textrm{trace}(M(\phi ))$ is a linear map.

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The Problem

Show that $\textrm{trace}: \textrm{End}(V)\rightarrow k$ defined by $\textrm{trace}(\phi ):=\textrm{trace}(M(\phi ))$ is a linear map.


My Question

I need some help with understanding the notation in this question. In other words, I am having a difficult time "reading the question." If anybody would be willing to dumb this down for me, I'd be incredibly grateful. I think once I understand how to start this proof, I will be be fine.

I understand:

  1. What $\textrm{trace}$ means.
  2. What $\textrm{End}(V)$ means.
  3. What a linear map is, and how to show that something is a linear map.

I do not understand:

  1. What $\phi$ means in this context.
  2. What $M(\phi)$ means.
  3. What $\textrm{trace}(M(\phi))$ means.

Additional Details

The book used is the course I am taking is Abstract Linear Algebra by Curtis, although this exercise may not be from the text itself.


As always, thank you all for your help.

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Nice job framing your question precisely!

  1. $\phi$ is the variable of this particular function. Just like the $x$ in $f(x) = x^2$. It stands for any member of $\operatorname{End}(V)$.

  2. I don't think it's standard notation, but from the context I gather that $M(\phi)$ is a matrix associated to $\phi$. Once you choose a basis $v_1, v_2, \dots v_n$ for $V$, you know that there are constants $(a_{ij})$ such that $$ \phi(v_j) = \sum_{i=1}^n a_{ij} v_i $$ for each $j$. Then $M(\phi)$ is the matrix whose $(i,j)$th entry is $a_{ij}$.

  3. Now you know that $M(\phi)$ is a matrix, it should be clear that $\operatorname{trace}(\phi)$ is the trace of this matrix.

Something to think about/prove: If you need to choose a basis to find $M(\phi)$, does the trace depend on that basis? If it does, trace is not a function on endomorphisms, only on matrices.

Then you have to show that the trace satisfies the linearity properties. But that should be straightforward.