I tried to do that:
$$(1+x)^p=1+px+\binom{p}{2}x^2+\dots+\binom{p}{p-1}x^{p-1}+x^p$$
So if $x=0 \quad mod(p^k)$ then $(1+x)^p=1 \quad mod(p^{k+1})$
Now I'm trying to deduce that $(1+p)^{p^{\alpha-1}}= 1 \quad mod(p^\alpha)$ but I don't know how to do it. Maybe recurrence?
Thank you