Show the operator is self-adjoint on a period function

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Let $V$ be a vector space of all $2\pi$-periodic function from $\Bbb R$ to $\Bbb C$ with the inner product:

$$\langle f,g \rangle =\int_0^{2\pi} \overline{f(x)}g(x)dx$$

$$A:V\to V, f\to \frac{df}{dx}$$

Now, my attempt

$$\langle Af,g \rangle =\int_0^{2\pi} \frac{\overline{f(x)}}{dx}g(x)dx=\overline{f(x)}g(x) \biggr |^{2\pi}_0-\int_0^{2\pi} \overline{f(x)}\frac{g(x)}{dx}dx$$

And here i'm stuck. This is supposed to equal to $\langle f,Ag\rangle$ to complete the answer right?

and second part:

Let $$U=\text{span}\{x \rightarrow e^{inx}=\sin(nx)+i \cos(nx) \mid n\in \Bbb Z\}$$

be the induced inner product. Find a orthonormal basis of U and the eigenvalues and eigenvectors of $A_{|U}$.

I don't quite understand what the second part wants me to do, appreciate any help!