Hint: Choose any even number to be $y$. Then $1+y^2$ is odd and is therefore the difference between two successive squares.
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Hint
Let $y=2k, z=2k^2$ and then complete the square on right hand side.
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Any number that is not of the form $4k+2$ is represented by the quadratic form $x^2-z^2$. So we just have to prove that for an infinite number of $y$, $y^2+1\not\equiv 2\pmod{4}$, but that holds for any even $y$.
Hint: Choose any even number to be $y$. Then $1+y^2$ is odd and is therefore the difference between two successive squares.