I want to show that the complex polynomial $p(z) = z^5 + 6z - 1$ has four different roots in the annulus $\{z \in \mathbb{C} : \frac{3}{2} < |z| < 2 \}$.
I used Rouché's theorem to proof that $p(z)$ has exactly four roots in the annulus, but I don't see why they should be different.
Any ideas? Thanks.
If they are not different, they are common roots of $p(z)$ and $p'(z)=5z^4+6$ and also of $5p(z)-zp'(z)=24z-5$ (but of course $\frac5{24}$ is not).