Showing that a matrix is singular

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Consider a matrix $A$ of dimension $4\times 4$ $$ A=\begin{pmatrix} a_{1} & a_2 & a_3 & a_4\\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ \end{pmatrix} $$ such that $a_1+a_2+a_3+a_4=1$ and $0\leq a_i\leq 1$ $\forall i \in \{1,2,3,4\}$.

Could you help me to show that this matrix is not invertible? In case the proof is too long, an intuition of the argument would be sufficient.

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It's an upper triangular matrix, so you can trivially calculate the determinant by multiplying the diagonals, which gives you a determinant of 0 meaning the matrix is non-invertible.