Showing that operations are under closure

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$GL(n)$ is the group of all invertible $n \times n$ matrices and $O(n)$ are all orthogonal $n \times n$ matrices.

I have to prove that $O(n) \subset GL(n)$.

I can prove that by showing that the neutral element of $GL$ is in $O$ and that the operations set of $O$, matrix multiplication and matrixinversion, are under closure.

How do I start with the second part?

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A matrix is orthogonal if and only if its inverse is its transpose, since they preserve inner (dot) products: $(x,y)=(Qx,Qy)$, which implies that $(x,Q^{-1}y)=(Qx,QQ^{-1}y)=(Qx,y)$. On the other hand, if $(Qx,y)=(x,Q^{-1}y)$, then we have $(Qx,Qy)=(x,Q^{-1}Qy)=(x,y)$.

Hence, $QQ^{T}=Q^{T}Q=I$, so inverses are okay.

On the other hand, for any $A,B \in O(n)$, that $(AB)^T=B^TA^T$, so we have that $AB(AB)^T=I$ by basic calculation