What has any operator got to do with dimensionality of the Hilbert space in which it is represented? Does a finite dimensional Hilbert space make sure that we have independent eigenvectors for the eigenvalues? If the Hilbert space is not finite, then also we will have infinite number of eigenvectors corresponding to different eigenvalues, isn't it?
2026-03-27 02:35:28.1774578928
Significance of finite dimensional vector space or Hilbert space
67 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in HILBERT-SPACES
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