How can we prove that x = 2 or 3 step-by-step:
$$(2-x)(3-x) = 0$$
I know the answer, but how do we get it without plugging in 2 and 3 directly?
Thank you!
How can we prove that x = 2 or 3 step-by-step:
$$(2-x)(3-x) = 0$$
I know the answer, but how do we get it without plugging in 2 and 3 directly?
Thank you!
A product in a ring with no divisors of zero can only be zero if one of the factors is zero and thus $$(2-x)(3-x)=0$$ implies $2-x=0$ or $3-x=0$.