Simple work done question I did it but the answer not matching

Question

An object moves along a certain path from point A with position vector $r_1 = 2i + 3j$ to point B with the position vector $r_2 = 3i - 2j$ under the Force $F = i +j$. Find out the work done by the force

What I did

$$W = F* S = (i+j)(r_2-r_1) =(i+j)(3i - 2j - 2i -3j) = -4$$

Answer sheet: 0

Answer 1

It seems like the correct answer is $W=-4$.

For easier computation, note that $W_{total}=W_i+W_j$

The general equation for $Work$: $$W=F*l$$

We calculate $W_1$:

$$W_i = F_i*(r_{2i}-r_{1i})=1*(3-2)=1*1=1$$

Now $W_2$:

$$W_j = F_j*(r_{2j}-r_{1j})=1*(-2-3)=1*(-5)=1$$

So

$W_{total}=W_i+W_j= 1-5=-4$