① Is there a point on a square with sides of rational length that is a rational distance from each vertex?
Note that this is a very specific case of the Rational Distance Problem, which can be expressed more simply as:
② Are there any Pythagorean triples (L, a, p) and (L, b, q) such that a + b = L?
I've done a computer search for small values (L < 2³¹) and found these pairs of triples such that a + b = L ± 1, but none any closer:
+-----------+----+-----------+-----------+
| L | ± | a | b |
+-----------+----+-----------+-----------+
| 1344 | -1 | 760 | 583 |
+-----------+----+-----------+-----------+
| 1600 | -1 | 1200 | 399 |
+-----------+----+-----------+-----------+
| 1508 | +1 | 1344 | 165 |
+-----------+----+-----------+-----------+
| 29040 | -1 | 28798 | 241 |
+-----------+----+-----------+-----------+
| 142912 | -1 | 82695 | 60216 |
+-----------+----+-----------+-----------+
| 594220 | -1 | 529371 | 64848 |
+-----------+----+-----------+-----------+
| 3751488 | +1 | 3049984 | 701505 |
+-----------+----+-----------+-----------+
| 17980480 | -1 | 10406328 | 7574151 |
+-----------+----+-----------+-----------+
| 40436800 | -1 | 30470799 | 9966000 |
+-----------+----+-----------+-----------+
| 65395616 | +1 | 34753887 | 30641730 |
+-----------+----+-----------+-----------+
| 95021927 | +1 | 87275664 | 7746264 |
+-----------+----+-----------+-----------+
| 189632508 | +1 | 168503165 | 21129344 |
+-----------+----+-----------+-----------+
| 234121100 | +1 | 208570992 | 25550109 |
+-----------+----+-----------+-----------+
| 283860000 | -1 | 182418750 | 101441249 |
+-----------+----+-----------+-----------+
| 513405900 | -1 | 395722000 | 117683899 |
+-----------+----+-----------+-----------+
Is there a simple disproof of ②?
Through elementary algebra, a precondition for ② is:
③ Are there non-trivial (i.e. distinct, strictly positive) integer solutions for a² - b² = p² - q²?
Which is equivalent to:
④ Are there non-trivial integer solutions for a² + q² = b² + p²?
Of which there are many examples, e.g. Numbers that are Sums of Squares in Several Ways
For 3, you can write it as $L^2=(a+b)(a-b)=(p+q)(p-q)$ so there are solutions for composite $L$. To make $a,b,p,q$ integers requires that $L$ be odd or a multiple of $4$. For example, $12^2=144=72\cdot 2=36\cdot 4=24 \cdot 6=37^2-35^2=20^2-16^2=15^2-9^2$ This doesn't get you 2, however.