First, I apologize for the title, but if I write my question then the characters will be too long.
Here's my question:
Why $(\frac{\log3}{\log2}+\frac{2\log3}{2\log2})(\frac{2\log2}{\log3}+\frac{\log2}{2\log3})=(2\times\frac{\log3}{\log2})(\frac{5}{2}\times\frac{\log2}{\log3})$ ?
I have no idea how the left side becomes the right side.
Because
$$\frac{\log3}{\log2}+\frac{\require{cancel}\cancel2\log3}{\cancel2\log2}=\frac{\log3}{\log2}+\frac{\log3}{\log2}=2\frac{\log3}{\log2}$$
and similarly
$$\frac{2\log2}{\log3}+\frac{\log2}{2\log3}=2\frac{\log2}{\log3}+\frac12\frac{\log2}{\log3}=\left(2+\frac12\right)\frac{\log2}{\log3}=\frac52\frac{\log2}{\log3}$$