Simplify the fractions

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First, I apologize for the title, but if I write my question then the characters will be too long.

Here's my question:

Why $(\frac{\log3}{\log2}+\frac{2\log3}{2\log2})(\frac{2\log2}{\log3}+\frac{\log2}{2\log3})=(2\times\frac{\log3}{\log2})(\frac{5}{2}\times\frac{\log2}{\log3})$ ?

I have no idea how the left side becomes the right side.

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There are 2 best solutions below

0
On BEST ANSWER

Because

$$\frac{\log3}{\log2}+\frac{\require{cancel}\cancel2\log3}{\cancel2\log2}=\frac{\log3}{\log2}+\frac{\log3}{\log2}=2\frac{\log3}{\log2}$$

and similarly

$$\frac{2\log2}{\log3}+\frac{\log2}{2\log3}=2\frac{\log2}{\log3}+\frac12\frac{\log2}{\log3}=\left(2+\frac12\right)\frac{\log2}{\log3}=\frac52\frac{\log2}{\log3}$$

0
On

multiplying this out and simplify: $$\frac{\log3\cdot 2\log2}{\log2\cdot\log3}+\frac{4\log3\cdot\log2}{2\log2\cdot\log3}+\frac{\log3\cdot\log2}{\log2\cdot2\log3}+\frac{2\log3\cdot\log2}{2^2\log2\cdot\log3}=...$$