simplifying exponential equation that has a natural logarithm

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I have the following equation:

$$y=\exp(C_1-C_2\ln x)$$

where $C_1$ and $C_2$ are constants.

I believe that the following is correct:

$$y=\exp C_1\exp (-C_2\ln x)$$

$\exp C_1$ is just a constant. I know that the exponent of the natural logarithm of $x$ is just $x$. But I'm not sure what to do with $C_2$.