Say, I'm comparing two functions
$f(n) = (ln(n))^2$ and $ g(n) = n^{0.01}$
as $n \rightarrow \infty$, by evaluating
$\lim_{n \rightarrow \infty } \frac{f(n)}{g(n)} = \lim_{n \rightarrow \infty } \frac{ln(n)^2}{n^{0.01}} $.
My question:
Am I justified in simplifying this by expressing $n$ as a function of $x \in \Re$, such that
$n(x) = e^x$,
so that the original limit becomes
$\lim_{x \rightarrow \infty } \frac{f(n(x))}{g(n(x))} = \lim_{x \rightarrow \infty } \frac{x^2}{e^{0.01x}} $ ?
2026-04-30 08:08:55.1777536535
Simplifying $f(n)$ by substituting, for $n$, an appropriately chosen function $n(x)$ to observe limiting behaviour of $f(n)$. Is this justified?
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1
The function $n=e^x$ is monotone, so it's justified. In this specific example you don't need to do it: $$ \lim_{n \to \infty} \frac{\log^a n}{n^s} = 0 $$
where $a,s>0$