How would I simplify a fraction that has a radical in it? For example:
$$\frac{\sqrt{2a^7b^2}}{{\sqrt{32b^3}}}$$
$$\frac{\sqrt{2a^7b^2}}{\sqrt{32b^3}}=\frac{\sqrt{2}\sqrt{a^6}\sqrt{a}\sqrt{b^2}}{\sqrt{16}\sqrt{2}\sqrt{b^2}\sqrt{b}}=\frac{a^3\sqrt{a}}{4\sqrt{b}}$$
Hint:
$$\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$$
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$$\frac{\sqrt{2a^7b^2}}{\sqrt{32b^3}}=\frac{\sqrt{2}\sqrt{a^6}\sqrt{a}\sqrt{b^2}}{\sqrt{16}\sqrt{2}\sqrt{b^2}\sqrt{b}}=\frac{a^3\sqrt{a}}{4\sqrt{b}}$$