Simplifying indices

Question

I have the question : simplify $$\frac{X^{1/3} \cdot X^{4/3}}{X^{-1/3}}.$$

So I have simplified as much as I could and got $$\frac{\sqrt[3] X \cdot \sqrt[3]{X^4}}{1/\sqrt[3] X}.$$

However the solutions says that the final answer should be $X^2$.

Answer 1

$$\frac{x^{1/3} \cdot x^{4/3}}{x^{-1/3}}=x^{1/3+4/3-(-1/3)}=x^{6/3}=x^2$$

Answer 2

You have

$$\frac{X^{1/3}X^{4/3}}{X^{-1/3}}=X^{1/3+4/3}X^{1/3}=X^{5/3+1/3}=X^{6/3}=X^2.$$