Six prime number form an arithmetic progression, what's the littlest value the last (sixth) term can have?
I saw this question and I didn't know how to solve. If there's like some key to solving to it let me know.
Six prime number form an arithmetic progression, what's the littlest value the last (sixth) term can have?
I saw this question and I didn't know how to solve. If there's like some key to solving to it let me know.
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7, 37, 67, 97, 127, 157 works.