When working with skew Schur functions, they can be defined as follows.
Let $C^{\lambda}_{\mu, \nu}$ be the integers such that
$$s_{\mu}s_{\nu}=\sum_{\lambda} C^{\lambda}_{\mu, \nu} s_{\lambda}$$
Then, we can define skew Schur functions as
$$s_{\lambda/\mu}= \sum_{\nu} C^{\lambda}_{\mu, \nu} s_{\nu}$$
My question is, if we can calculate each of this $s_{\mu}$, $s_{\nu}$, and $s_{\lambda}$, why can't we find $C^{\lambda}_{\mu, \nu}$ sometimes?
My teacher told me that something very different is to have a formula and to have an explicit product. He told me that these coefficients are not always easy to compute. And I have seen in some papers that it is equal to the number of tableaux such that has shape $\lambda$ and whatever. I mean, they use another methods to compute such coefficients.
Why does this happens if we know how to compute all but one object in this formula?
Of course, you can compute the Littlewood-Richardson coefficients by multiplying out $s_\mu s_\nu$ and expanding it in the Schur basis. But this isn't very efficient -- you cannot compute directly in the Schur basis (unless you already know the Littlewood-Richardson coefficients), so you would have to convert $s_\mu$ and $s_\nu$ into another basis (e.g., monomial or complete homogeneous) first, then multiply out, then convert the result back.