After looking for the asymptotes of the function:
$y^3+2y^2-x^2*y+y-x+4=0$
I found the answers y=0, y=-x-1 and y=x+1. This is almost exact: the last one should actually be y=x-1.
To find the result, I substituted x=my+c in the equation, which yielded $m=\pm 1$ and $c=\mp 1$, when c should be only -1. I can't find where I made a mistake. Any idea?
Benox
Let's look for asymptote :
$y=a\cdot x+b$
substitute into original equation:
$x^3\cdot a\cdot (a^2-1)+x^2\cdot (3a^2\cdot b+2\cdot a^2-b)+x\cdot ...+\ const$
so from $a\cdot (a^2-1)=0$, $a=0,1,-1$ use $3a^2\cdot b+2\cdot a^2-b$ to find corresponding b values $b=0,-1,-1$