So I have a question. I got a number in 6*1*8 where the total number has to be divisible with 9 and not 8. How do I find * (the two unknown digits)?

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I kinda know the answer from just guessing and trying to input different numbers but I probably should use something like divisibility rule of 3 or 9 or something but I struggle. Answer I got:

  • 60 138,
  • 62 118,
  • 63 108,
  • 63 198,
  • 64 188,
  • 65 178,
  • 67 158,
  • 68 148,
  • 69 138,
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The sum of the digits must be divisible by 9 for the whole number to be divisible by 9.

The last 3 digits of the number must be divisible by 8 , for the whole number to be divisible by 8.