Soluble(solvable) and nilpotent groups

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Defn 1.1. Let $\gamma _{0}(G)=G$, and $\gamma _{c}(G)=[\gamma _{c-1}(G),G]$ for $c\geq 1$. The lower central series of $G$ is a chain of subgroups of $G$: $$G=\gamma_0(G) \geq \gamma_1(G) \geq \cdots \geq \gamma_{c}(G)=1,$$ where the least such $c$ is called the nilpotency class of $G$.

Defn 1.2. Let $G^{(0)}=G$, and $G^{(d)}=[G^{(d-1)},G^{(d-1)}]$ for $d\geq 1$. The derived series of $G$ is a chain of subgroups of $G$: $$G=G^{(0)}\geq G^{(1)}\geq \cdots \geq G^{(d)}=1,$$ where the least such $d$ is called the derived length of $G$.

Defn 2.1. A group $G$ is nilpotent if $\gamma _{c}(G)=1$ for some $c\geq 0$.

Defn 2.2. A group $G$ is soluble(solvable) if $G^{(d)}=1$ for some $d\geq 0$.

It follows from the definitions that $\gamma_1(G)=[G,G]=G^{(1)}$. On the other hand, $\gamma_2(G)=[\gamma_1(G),G]=[[G,G],G]=[\gamma_1(G),G]$ while $G^{(2)}=[G^{(1)},G^{(1)}]=[\gamma_1(G),\gamma_1(G)]$.

My questions are as follows:

  1. We know that $G^{(i)}$ is a subgroup of $\gamma_i(G)$ for all $i$. How can we use it to show that every nilpotent group is solvable?

  2. What are the examples of soluble groups that are not nilpotent?

Thanks in anticipation.

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As you say you know $\;G^i\le\gamma_i\;$, if $\;G\;$ is nilpotent there exists $\;c\in\Bbb N\;$ s.t. $\;\gamma_c=1\;$ , and this means $\;G^c\le\gamma_c=1\implies G^c=1\;$ , which means $\;G\;$ is soluble...

OTOH, I think it'd be easier to observe that any central series (say, as the lower central or the upper central series) is always abelian...