I'm revising some old psets while preparing an exam and going through some things that I left unverified.
How many relations of equivalence $R$ are there in $\Bbb N$ that verify silmultaneously the following properties?
- If two elements end in the same digit, they are related
- {(1,2),(101,25),(4,4),(234,20166),(22,7),(153,158),(8,100),(17,27)}$⊆R$
- (1,14),(32,8),(19,10),(309,666) $\notin R$
This would give me the following equivalence classes if I'm not wrong:
$[1] = [2] = [5] = [7]$
$[0] = [3] = [8]$
$[4] = [6]$
$[9]$
The thing is that I'm not understanding how to use the third property, so that makes me think I got the previous wrong. Can you help me out?
This answer starts where you stopped. We focus on the $4$ sets $[1],[0],[4],[9]$. Any equivalence relation with the mentioned properties will induce a partition such that each of its elements is a non-empty union of these sets.
We have $[1]\cup[0]\cup[4]\cup[9]=\mathbb N$, but what can be said about mutually disjointness? On this the third property applies the following information:
Note that $[1]\cap[9]\neq\varnothing$ or equivalently $[1]=[9]$ is not excluded.
Also note that $[0]\cap[4]\neq\varnothing$ or equivalently $[0]=[4]$ is not excluded.
This makes $4$ partitions possible:
The answer on the original question (number of equivalences) is $4$.