let $A$ be a leibniz algebra over an algebrically closed field $K$ of characteristic $0$. I think if $A$ has basis $e_i$ ,$f_j$ , for $i=1,2,...,m$ and $j=1,2,...,n$, with $e_if_j=\lambda_{ij}f_j$, either $e_if_j=-f_je_i$, or $f_je_i=0$, and all other products between basis elements equal to $0$. is solvable leibniz algebra.
is it true? I want to this statement to levi theorem
thanks for help